Question

Solution

Correct option is

121.6 nm

Wavelengths in Balmer series for hydrogen are given by

The second line in Balmer series corresponds to n = 4. Hence

The wavelength of the first line (n = 2) in Lyman series is

121.6 nm.

SIMILAR QUESTIONS

Q1

The innermost orbit of the hydrogen atom has diameter of 1.06 Å. What is the diameter of the tenth orbit?

Q2

The difference lines in the Lyman series have their wavelengths lying between

Q3

The shortest wavelength in the :Lyman Series is 911.6 Å. Then the longest wavelength in the Lyman’s Series is

Q4

Which of the following transition in a hydrogen atom emits the photon of lowest frequency?

Q5

How many times does the electron go around the first Bohr orbit in one second?

Q6

The electron orbits with principal quantum numbers n > 3 were not allowed, the number of possible elements would be

Q7

According to Bohr’s theory, the energy of an electron in the nth orbit of an atom of atomic number Z is proportional to

Q8

The dimensions of the Rydberg’s constant are

Q9

In terms of the Rydberg’s constant R, the minimum wavelength in the Lyman series is

Q10

The wavelength of the first line in Balmer series in the hydrogen spectrumis . What is the wavelength of the second line.