Question
Two springs A and B have force constants k_{1} and k_{2} respectively. The ratio of the work done on A to that done on B when they are stretched by the same force is

k_{1}/k_{2}

k_{2}/k_{1}


easy
Solution
k_{2}/k_{1}
When the springs are stretched by the same force F, the extensions in springs A and B are x_{1} and x_{2} respectively which are given by
Using (i) and (ii) we get
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