## Question

Water from a tap emerges vertically downward with an initial speed of 1.0 ms^{–1}. The cross-sectional area of the tap is 10^{–4} m^{2}. Assume that the pressure is constant throughout the stream of water, and that the flow is steady. The cross-sectional area of the stream 0.15 m below the tap is : (g = 10 m/s^{2})

### Solution

By Bernoulli’s theorem,

Here *h*_{1} = 0, *h*_{2} = –0.15 m, *v*_{1} = 1.0 m/s and *g* = 10 ms^{–2}

Solving *v*_{2} = 2.0 ms^{–1}

Now, from continuity eq.

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#### SIMILAR QUESTIONS

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