## Question

### Solution

Correct option is

2.75

Let X denotes the number of units. Then, X is a random variable with the following probability distribution

 xi: 0 1 2 3 4 5 pi: 0.15 0.2 0.1 0.05 0.3 0.2   #### SIMILAR QUESTIONS

Q1

If X follows a binomial distribution with parameters n = 100, p = 1/3, then P(X = r) is maximum when r =

Q2

A team of 8 couples, (husband and wife) attend a lucky draw in which 4 persons picked up for a prize. Then, the probability that there is at least one couple is

Q3

An unbiased die with faces marked 1, 2, 3, 4, 5 and 6 is rolled four times. Out of four face values obtained, the probability that the minimum face value is not less than 2 and the maximum face value is not greater than 5 is

Q4

If X following a binomial distribution with parameters n = 8 and p = 1/2, then equals

Q5

Two numbers b and c are chosen at random with replacement from the numbers 1, 2, 3, 4, 5, 6, 7, 8 and 9. The probability that x2 + bx + c > 0 for all x Ïµ R is

Q6

India plays two matches each with west indies and Australia. In any one match, the probabilities of India getting points 0, 1, 2 are respectively 0.45, 0.05 and 0.05 and 0.50 for base drawn and won. Assuming that the outcomes are independent, the probability of India getting at least 7 points is

Q7

If two events A and B are such that P(AC) = 0.3, P(B) = 0.4 and P(ABC) = 0.5 then P(B/A  BC) =

Q8

A bag contains n + 1 coins. It is known that one of these coins shows heads on both sides, whereas the other coins are fair. One coin is selected at random and tossed. If the probability that toss results in heads is 7/12, then the value of n is

Q9

In a game, a person is paid Rs. 5 if he gets all heats or all tails when three coin are tossed, and he will pay Rs. 3 if either one or two heads shown. What can be expect to win on the average per game?

Q10

Four bad oranges are mixed accidently with 16 good oranges. Find the probability distribution of the number of bad oranges in a draw of oranges.