A Jet Airplane Traveling From East To West At A Speed Of 500 Kmh–1 ejects Out Gases Of Combustion At A Speed Of 1500 Kmh–1 with Respect To The Jet Plane. What Is The Velocity Of The Gases With Respect To An Observer On The Ground?     

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Question

A jet airplane traveling from east to west at a speed of 500 kmh–1 ejects out gases of combustion at a speed of 1500 kmh–1 with respect to the jet plane. What is the velocity of the gases with respect to an observer on the ground?   

 

Solution

Correct option is

1000 km h–1 in the direction west to east 

Suppose, the choose the positive direction to be from east to west. Then the velocity of the plane = +500 km h–1. Since the gases are ejected in the direction opposite to the direction of motion of the plane, the relative velocity of the gases with respect to the plane = –1500 km h–1. Therefore, the velocity of the gases with respect to an observer on the ground = –1500 + 500 = –1000 km h–1. The negative sign indicates that the direction of the velocity is from west to east.

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