﻿ A ray emanating from the point (5, 0) is incident on the hyperbola 9x2 – 16y2 = 144 at the point P with abscissa 8. Find the equation of the reflected ray after first reflection and point P lies in first quadrant.   : Kaysons Education

# A Ray Emanating From The Point (5, 0) Is Incident On The Hyperbola 9x2 – 16y2 = 144 At The Point P with Abscissa 8. Find The Equation Of The Reflected Ray After First Reflection And Point P lies In First Quadrant.

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## Question

### Solution

Correct option is

Given hyperbola is 9x2 – 16y2 = 144. This equation can be rewritten as

Since x coordinates of P is 8. Let y coordinate of P is α.

Hence coordinates of point P is

âˆµ Equation of reflected ray passing through

∴ Its equation is

.

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