If A, B, C, … Are In G.P., And A1/x = B1/y = C1/z = …, Then X, Y, Z, … Are In

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Question

If a, b, c, … are in G.P., and a1/x = b1/y = c1/z = …, then x, y, z, … are in

Solution

Correct option is

A.P.

               

Now, use log a, log b, log c, … are in A.P.

SIMILAR QUESTIONS

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Four geometric means are inserted between 211 – 1 and 211 + 1. The product of these geometric means is

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Let a, b, c > 0 and a, b, c be in A.P. If a2, b2, c2 are in G.P., then