Question

Sodium metal crystallizes as a body centred cubic lattice with the cell edge 4.29 . What is the radius of sodium atom?

Solution

Correct option is

1.857 × 10-8 cm

SIMILAR QUESTIONS

Q1

The interionic distance for cesium chloride crystal will be

Q2

For cubic coordination, the value of radius ratio is

Q3

The ratio of cationic radius of anionic radius in an ionic crystal is greater than 0.732. its coordination number is

Q4

The vacant space in the bcc unit cell is

Q5

Calculate the ionic radius of a Cs+ ion, assuming that the cell edge length for CsCl is 0.4123 nm and that the ionic radius of a Cl- ion 0.181 nm.

Q6

If the value of ionic radius ratio  is 0.52 in an ionic compound, the geometrical arrangement of ions in crystal is

Q7

A metal has bcc structure and the edge length of its unit cell is 3.04 . The volume of the unit cell in cm3 will be

Q8

For an ionic crystal of the general formula AX and coordination number 6, the value of radius ratio will be

Q9

In A+ B- ionic compound, radii of A+ and B- ions are 180 pm and 187 pm respectively. The crystal structure of this compound will be

Q10

An fcc lattice has a lattice parameter a = 400 pm. Calculate the molar volume of the lattice including all the empty space.