## Question

### Solution

Correct option is

FourFe2+ and four O2-

Let the units of ferrous oxide in a unit cell = n. Molecular weight of ferrous oxide (FeO)

= 56 + 16 = 72g mol-1

Weight of n unit =

Volume of one unit = (length of corner)3

= 4.27 = 4

#### SIMILAR QUESTIONS

Q1

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Q2

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Q4

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Q7

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Q8

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Q9

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Q10

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