Let A be The Centre Of The Circle x2 + y2 – 2x – 4y – 20 = 0. The Tangents At The Point B(1, 7) And C(4, –2) On The Circle Meet At The Point D. If Δ Denotes The Area Of The Quadrilateral ABCD, Then 45Δ Is Equal To

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Question

Let A be the centre of the circle x2 + y2 – 2x – 4y – 20 = 0. The tangents at the point B(1, 7) and C(4, –2) on the circle meet at the point D. If Δ denotes the area of the quadrilateral ABCD, then 45Δ is equal to

Solution

Correct option is

3375

Tangents at B and C are respectively 

             x + 7y – (x + 1) – 2(y + 7) – 20 = 0  

and       4x – 2y – (x + 4) – 2(y – 2) – 20 = 0   

⇒         y = 7 and 3x – 4y – 20 = 0    

They intersect at D(16, 7).  

Coordinates of A are (1, 2)    

Area of the quadrilateral ABCD   

= 2 Area of the triangle ABD

 

    

   

 

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