﻿ A focal chord of parabola y2 = 4x is inclined at an angle of  with the +ive direction of x-axis, then the slope of normal drawn at the ends of focal chord will satisfy the equation : Kaysons Education

# A Focal Chord Of Parabola y2 = 4x is Inclined At An Angle Of  with The +ive Direction Of X-axis, Then The Slope Of Normal Drawn At The Ends Of Focal Chord Will Satisfy The Equation

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#### SIMILAR QUESTIONS

Q1

Consider the two curves C1 : y2 = 4xC2 : x2 + y2 – 6x + 1 = 0. Then,

Q2

Angle between tangents drawn from the point (1, 4) to the parabola y2 = 4is

Q3

The angle between the tangents drawn from the origin to the parabola y2 = 4a(x – a) is

Q4

The equation of the common tangent touching the circle (x – 3)2 + y2 = 9 and the parabola y2 = 4x above the x-axis is

Q5

The equation of the common tangent to the curves y2 = 8x and xy = –1 is

Q6

A tangent and a normal are drawn at the point P(16, 16) of the parabola y2 = 16x which cut the axis of the parabola at the points A and B respectively. If the center of the circle through P, A and B is C, then angle between PC and axis of x is

Q7

If x + y = k is normal to y2 = 12x, then k is

Q8

A circle drawn on any focal chord AB of the parabola y2 = 4axas diameter cuts the parabola again at and D. If the parameters of the points A, B, C, D be t1, t2 t3 and t1 respectively, then the value of t3 t4 is

Q9

The length of normal chord which subtends an angle of 900 at the vertex of the parabola y2 = 4x is

Q10

If two different tangents of y2 = 4x are the normal’s to the parabola x2 = 4ay, then