Show That The Lines 2x – y – 12 = 0 And 3x + y – 8 = 0 Intersect At A Points Which Is Equidistant From Both The Coordinates Areas.

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Show that the lines 2x – y – 12 = 0 and 3x + y – 8 = 0 intersect at a points which is equidistant from both the coordinates areas.


Correct option is

(4, –4)

2x – y – 12 = 0  

3x + y – 8 = 0  

Using cross multiplication rule, we have


So, the point is (4, –4) which is at a distance 4 units from both the coordinate axes.



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