Question

Find the area of triangle formed by the lines x – y + 1 = 0, 2x + y + 4 = 0 and x + 3 = 0.  

Solution

Correct option is

8/3

             

where C­1 = (2) (0) – (1) (1) = –1   

           C2 = –[(1) (0) – (1) (–1) = –1         

           C3 = (1) (1) – (2) (–1) = 3    

Putting these values, we get 

       

                                                    (expanding along last row) 

                

SIMILAR QUESTIONS

Q1

Find the acute angle between the two lines with slopes 1/5 and 3/2.

Q2

If a line has a slope = ½ and passes through (–1, 2); find its equation. 

Q3

If a line has a slope 1/2 and cuts off along the positive y-axis of length 5/2 find the equation of the line.

Q4

If a line passes through two points (1, 5) and (3, 7) find its equation.

Q5

A straight line passes through a point A (1, 2) and makes an angle 60owith the x-axis. This line intersects the line x + y = 6 at the point P. find AP.

Q6

Find the equation of the straight line, which passes through the point (3, 4) and whose intercept on y-axis is twice that on x-axis.

Q7

Find the equation of the straight line upon which the length of perpendicular from origin is  units and this perpendicular makes an angle of 75o with the positive direction of x-axis.

Q8

Find the value of k so that the straight line 2x + 3y + 4 + k (6x – y + 12) = 0 and 7x + 5y – 4 = 0 are perpendicular to each other.

Q9

Show that the lines 2x – y – 12 = 0 and 3x + y – 8 = 0 intersect at a points which is equidistant from both the coordinates areas.

Q10

The line x + λy – 4 = 0 passes through the point of intersection of 4x – y+ 1 = 0 and x + y + 1 = 0. Find the values of λ.