Question

A beam of -particles of velocity  is scattered by a gold (Z = 79) foil. Find out the distance closest approach of the -particle to the gold nucleus. The value of charge/mass for -particle is .

Solution

Correct option is

When the -particle reaches the nucleus to the closest distance r0, whole of its kinetic energy  is converted into electrostatic potential energy . Then  

              

   

Substituting the given values : 

    

         .

SIMILAR QUESTIONS

Q1

The energy of a photon is give as Then the wavelength  of a photon is.

Q2

The ratio of ionization energy of hand is  is

Q3

Potential energy of list electron is

Q4

The ratio of ionization energy of hydrogen atom in terms of Reedley constant  is given

Q5

An -part ale of energy 5Mev is scattered through 180 by a fined uranium nucleus. The distance of the closed approach is of the order of:

Q6

An -particle with kinetic energy 10 MeV is heading towards a stationary point-nucleus of atomic number Z = 50. Calculate the distance of closest approach.

   

Q7

 

An -particle with kinetic energy 10 MeV is heading towards a stationary point-nucleus of atomic number Z = 50. Calculate the distance of closest approach.

   

Q8

What is the distance of closest approach when a 5.0 MeV proton approaches a gold nucleus (Z = 79)? Given, 

    

.

Q9

An -particle after passing through a potential difference of  falls on a silver foil. The atomic number of silver is 47. Calculate the kinetic energy of the -particle at the time of falling on the foil. 

Q10

What is the upper limit of the radius of the gold nuclues (Z = 79), if an -particle of energy 12.5 MeV is deflected back by the nucleus through 180o.