The Energy Released By The Fission Of One Uranium Atom Is 200 MeV. The Number Of Fissions Per Second Required To Produce 3.2 W Of Power Is

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Question

The energy released by the fission of one uranium atom is 200 MeV. The number of fissions per second required to produce 3.2 W of power is

Solution

Correct option is

1017

Energy released = 200 MeV 

                           

                           

Therefore, the required number is 

         .

SIMILAR QUESTIONS

Q1

If an orbital electron of the hydrogen atom jumps from the ground state to a higher energy state, its orbital speed reduces to half its initial value. If the radius of the electron orbit in the ground state is r, then the radius of the new orbit would be  

Q2

The orbital speed of the electron in the ground state of hydrogen is v. What will be its orbital speed when it is excited to the energy state –3.4eV. 

Q3

The ratio of the wavelengths of the longest wavelength lines in the Lyman and Balmer series of hydrogen spectrum is 

Q4

If a hydrogen atom at rest, emits a photon of wavelength , the recoil of the atom of mass m is given by

Q5

In an atom there are p photons, n neutrons and e electrons. For atoms of small mass, the relation between pn and e is   

Q6

Cal to protons ever attract each other?

Q7

How much energy is released when one amu is wholly converted into energy?

Q8

In the equation     

           ,  

The correct symbol for X is

Q9

The kinetic energy of a 300 K thermal neutron is

Q10

The binding energy of deuteron  is 1.15 MeV per nucleon and an alpha particle  has a binding energy of 7.1 MeV per nucleon. Then in the reaction 

             

the energy Q released is