﻿ Suppose ax + bx + c = 0, where a, b, c are in A.P. be normal to a family or circles. The equation of the circle of the family which intersects the circle x2 + y2 – 4x – 4y – 1 = 0 orthogonally is : Kaysons Education

# Suppose ax + bx + c = 0, Where a, b, c are In A.P. Be Normal To A Family Or Circles. The Equation Of The Circle Of The Family Which Intersects The Circle x2 + y2 – 4x – 4y – 1 = 0 Orthogonally Is

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## Question

### Solution

Correct option is

x2 + y2 – 2x + 4– 3 = 0

abc are in A.P., so ax + by + c = 0 represents a family of lines passing through the point (1, –2). So, the family of circles (concentric) will be given by x2 + y2 – 2x + 4y + c = 0.

And

#### SIMILAR QUESTIONS

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Q2

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Q3

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Q5

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Q6

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Q7

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Q10

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