Find the maximum and minimum values of
Now the maximum value of is and minimum value is -1.
Hence the maximum value and minimum value
The number of solution of the equation
If tan x = 2b/(a – c) (a ≠ c), y = a cos2 x + 2b sin x cos x + c sin2 c and z = a sin2 x – 2b sin x cos x + c cos2 x, then
If A and B are acute angles such that sin A = sin2 B, 2cos2 A = 3 cos2 B; then
If cos (θ – α), cos θ and cos (θ + α) are in harmonic progression, then cosθ sec (α/2) is equal to
If A and B are acute angles such that A + B and A – B satisfy the equation tan2 θ – 4 tan θ + 1 = 0, then find the value of A and B.
Find the possible integral values of a for which cos 2x + a sin x = 2a – 7 has solutions.
Simplify the product cos A cos 2A. cos22A…..cos2n-1A.
If cos 5θ = a cos θ + b cos3 θ + c cos5 θ + d, then