How much of NaOH is required to neutralize 1500 cm3 of 0.1 N HCl? (Na = 23)
= 0.15 g eq.
It will neutralize NaOH = 0.15 g eq.
50mL 10 N H2SO4, 25mL 12 N HCl and 40 mL 5 N HNO3 were mixed together and the volume of the mixture was made 1000mL by adding water. The normality of the resultant solution will be :
The number of atoms in 4.25 g of NH3 is approximately
A 100mL solution of 0.1 N HCl was titrated with 0.2 N NaOH solution. The titration was discontinued after adding 30mL of NaOH solution. The remaining titration was completed by adding 0.25 N KOH solution. The volume of KOH required for completing the titration is
One mole of calcium phosphide on reaction with excess of water gives
Number of g of oxygen in 32.2 g Na2SO4. 10H2O is
The percentage of Se in peroxidase anhydrous enzyme is 0.5% by weight (atomic weight = 78.4). Then minimum molecular weight of peroxidaseanhydrous enzyme is
The percentage of nitrogen in urea is about
10 dm3 of N2 gas and 10 dm3 of gas X at the same temperature contain the same number of molecules. The gas X is
The volume of water to be added to 100 cm3 of 0.5 N H2SO4 to get decinormal concentration is
250mL of a sodium carbonate solution contains 2.65 grams of Na2CO3. If 10mL of this solution is diluted to one litre, what is the concentration of the resultant solution?
(mol. wt. of Na2CO3= 106)