Question

CsCl crystallizes in a cubic lattice that has a Cl- at each corner and Cs+ at the centre of the unit cell. What is the value of edge length a of the cube?  

Solution

Correct option is

4.04

 

The closest Cs+ to CI- distance = sum of the ionic radii of Cs+  and CI-

                                                         = 1.69  + 1.81

                                                         

The distance in one – half of the cubic diagonal =    

                                                                        

                                                                         

 

SIMILAR QUESTIONS

Q1

A metal crystallizes into two cubic phases fcc and bcc whose unit cell lengths are 3.5 and 3.0 Å respectively. What is the ratio of densities of fcc and bcc?

Q2

The radius of a divalent cation M2+ is 94 pm and that of divalent anion X2–is 146 pm. Thus, M2+ X2– has

Q3

MgO has a structure of NaCl, the coordination number of O2– in MgO is

Q4

If NaCl is doped with 10–3 mol% of SrCl2, calculate the concentration of cation vacancies

Q5

The composition of a sample of wustite is Fe0.93 O. What percentage of the iron is present in the form of  Fe III?

Q6

The first order reflection of a beam of  X – rays of wavelength  from the (210) plane of a crystal of the simple cubic type, occurs at an angle of 11.290, the length of the unit cell is

Q7

A solid AB has the NaCI structure. If radius of cation A+ is 120 pm, the maximum possible value of the radius of the anion B- is

Q8

 

KCI crystallises in the same type of lattice as does NaCI.

   

The ratio of the side of the unit cell for NaCI to that for KCI is

Q9

The unit cell of aluminum is a cube with an edge length of 405 pm. The density of aluminum is 2.70 g cm-3. The type of unit cell is

Q10

A binary solid X+ Y- has a zinc blende structure with Y- ions forming the lattice and X+ ion occupying 25% tetrahedral sites. The formula of the solid is