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Acceleration & Velocity - One Dimensional Motion JEE Chapterwise Analysis, Weightage and Overview

Vectors add a new dimension to the kit of the students. This chapter introduced basic formulas and equations. While questions directly do not appear from the chapter as only 3 questions have been asked in the past 10 years. Understand the intuition behind the simple equations and it will be useful in all the upcoming chapters. A simple understanding of various graphs is useful as well. .

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1-D Motion JEE 0 1 0 0 0 0 0 1 1 0 0

 

List of important topics One dimensional motion JEE

  • Position and Displacement.
  • Velocity and Acceleration

One dimensional motion JEE Syllabus

  • Position and Displacement, Average Velocity, Velocity and Acceleration, Graphing Motion, Motion.

Download One dimensional motion JEE Notes

 
One dimensional motion Download

Velocity and Acceleration JEE Test Series 2022,2023,2024

List of FREE Tests  
Paper set 1 Download Questions Download Solutions

Practice Acceleration & Velocity JEE Questions with solutions

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Q.

A 2m wide truck is moving with a uniform speed  along a straight horizontal road. A pedestrian starts to cross the road with a uniform speed vwhen the truck is 4 m way from him. The minimum value of v so that he can cross the road safely is :

                                                           

Q.

Column-1 gives some graphs for a particle moving along x-axis in positive x-direction. The variables vx and t represent speed of particle, x-coordinate of particle and time respectively. Column-2 gives certain resulting interpretation. Match the graphs in Column-1 with the statements in Column-2.

           Column 1

           Column 2

 (A)

           

 (p)

 Acceleration of particle is  uniform

 (B)

           

 (q)

 Acceleration of particle is  non-uniform

 (C)

              

 (r)

 Acceleration of particle is  directly proportion to ‘t’

 (D)

           

 (s)

 Acceleration of particle is  directly proportional to ‘x’

 

Q.

The equation of motion of the particle is described in Column 1. At t = 0, particle is at origin and at rest. Match the Column 1 with the statements in Column 2.

            Column 1

                Column 2

 (A)

   

 (p)

 Velocity of particle at t = 1 s is 8  m/s

 (B)

  

(q)

 Particle moves with uniform  acceleration

 (C)

  

 (r)

 Particle moves with variable  acceleration

 (D)

  

 (s)

 Particle will change its direction at  some time.

 

Q.

A point moves along a straight line with deceleration whose magnitude depends on the speed as  At t = 0, velocity of the point is 4 m/s, and displacement is 0.

             Column 1

           Column 2

 (A)

 Time when velocity is zero.

 (p)

 2 s

 (B)

 Time (approximately) when  magnitude of displacement is 16/3 m.

 (q)

 4 s

 (C)

 Time when displacement is 14/3 m.

 (r)

 6 s

 (D)

 Time when velocity is 1 m/s

 (s)

 9 s

 

Q. An engine of a train moving with uniform acceleration passes an electric pole with velocity u and the last compartment with velocity v . the middle part of train passes the same pole with a velocity ...... thus my question please explain the concept behind it and also slution in detail.?

Answer (1) length of train :- l When last compartment passes through pole distance covered by first compartment is l ∴v 2 =u 2 +2al ∴a= 2l v 2 −u 2 ​ Now, when middle post passes, distance covered by first compartment is 2 l ​ ∴v f 2 ​ =u 2 + 2 Ral ​ =u 2 +( 2l v 2 −u 2 ​ )l= 2 v 2 +u 2 ​ ∴v f ​ = 2 v 2 +u 2 ​

Q. Tell when should we use acceleration as -g and g. also tell when should we use displacement as -x and x when a body moves either upwards or downwards?

suppose you have taken upward direction as positive and downwards as negative from starting point , then when ball is moving upwards , displacement will be + x and gravity will be -g because it is acting downwards.
now if ball is moving down , then displacment will be -x and gravity will be +g

Q. A juggler keeps on moving four balls in the air throws the balls in regular interval of time when one ball leaves his hands with speed 20m/s the position of other balls will be ( G=10m/s^2) I am not getting answer please tell how to solve this question step by step.?

The height of ball 1 is 15 m, of ball 2 is 20 m and of ball 3 is 20 m respectively.


Time taken by same ball to return to the hands of juggler =2u / g ( use equation of motion , with displacement = 0)


= 2×20 / 10 = 4s.


Therefore he is throwing the balls after each 1s.( given in question equal interval)

Let at some instant he is throwing ball number 4.

Before 1s of it he throws ball 3.

So height of ball 3


h3 = 20 × 1 − 1 / 2 x 10(1)^2 = 15 m


Before 2s, he throws ball 2. So height of ball 2 is


h2 = 20 × 2 − 1 / 2 x 10(2)^2 = 20 m


Before 3s, he throws ball 1. So height of ball 1 :


h1 = 20 × 3 − 1 / 2 x 10(2)^2 = 20 m


Hence the height of ball 1 is 15 m, of ball 2 is 20 m and of ball 3 is 20 m respectively.