Find the equation of circle which touches axis of y at a distance 4 units from the origin and cuts the intercept of 6 units from the axis of x.
Equation of circle in intercepts
âˆµ CM = NO = 4
∴ PC = 5
Radius of circle = 5
∴ NC = 5
Centre of circle is (5, 4)
∴ Equation of circle, if centre in I quadrant
(x – 5)2 + (y – 4)2 = 25,
(x + 5)2 + (y + 4)2 = 25
And (x – 5)2 + (y + 4)2 = 25
Hence, there are 4 circle which satisfy the given conditions. They are
Find the equation of the circle the end points of whose diameter are the centers of the circle.
x2 + y2 + 6x – 14y = 1 and x2 + y2 – 4x + 10y = 2
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Find the equation of the circle which passes through the points (4, 1), (6, 5) and has its centre on the line 4x + y = 16.
Find the equation of circle passing through the three non-collinear points (1, 1), (2, –1) and (3, 2).
Find the equation of the circle whose diameter is the line joining the points (–4, 3) and (12, –1). Find also the intercept made by it on y axis.
Find the equation of the circle which passes through the origin and makes intercepts of length a and b on axis of x and y respectively.
A circle of radius 2 lies in the first quadrant and touches both the axes of coordinate. Find the equation of circle with centre at (6, 5) and touching the above circle externally.
A circle of radius 5 units touches the coordinates axes in 1st quadrant. If the circle makes one complete roll on x axis along positive direction of xaxis. Find the equation in new position.
Discus the position of the points (1, 2) and (6, 0) with respect to the circle.
x2 + y2 – 4x + 2y – 11 = 0