﻿ The sides of a square are x = 2, x = 3, y = 1, y = 2 find the equation of the circle drawn on the diagonals the square as its diameter. : Kaysons Education

# The Sides Of A Square Are x = 2, x = 3, y = 1, y = 2 Find The Equation Of The Circle Drawn On The Diagonals The Square As Its Diameter.

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## Question

### Solution

Correct option is

x2 + y2 – 5x – 3y + 8 = 0

Let ABCD be a square and equation of its sides ABBCCD and DA arey = 1, x = 3, y = 2 and x = 2 respectively.

Then diagonals of squares are the diameters of the circle, then equation of circle is

(x – 2) (x – 3) + (y – 1)(y – 2) = 0

⇒    x2 + y2 – 5x – 3y + 8 = 0             (If AC as diameter)

#### SIMILAR QUESTIONS

Q1

Find the equation of the circle the end points of whose diameter are the centers of the circle.

x2 + y2 + 6x – 14y = 1 and x2 + y2 – 4x + 10y = 2

Q2

The abscissas of two point A and B are the roots of the equation x2 + 2ax – b2 = 0 and their ordinate are the roots of the equation x2 + px – q2 = 0. Find the equation and the radius of the circle with AB as diameter.

Q3

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Q4

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Q5

Find the equation of the circle whose diameter is the line joining the points (–4, 3) and (12, –1). Find also the intercept made by it on y axis.

Q6

Find the equation of circle which touches axis of y at a distance 4 units from the origin and cuts the intercept of 6 units from the axis of x.

Equation of circle in intercepts

Q7

Find the equation of the circle which passes through the origin and makes intercepts of length a and b on axis of x and y respectively.

Q8

A circle of radius 2 lies in the first quadrant and touches both the axes of coordinate. Find the equation of circle with centre at (6, 5) and touching the above circle externally.

Q9

A circle of radius 5 units touches the coordinates axes in 1st quadrant. If the circle makes one complete roll on x axis along positive direction of xaxis. Find the equation in new position.

Q10

Discus the position of the points (1, 2) and (6, 0) with respect to the circle.

x2 + y2 – 4x + 2y – 11 = 0