Question

Solution

Correct option is

                 

      

SIMILAR QUESTIONS

Q1

For natural number mn if (1 – y)m (1 + y)n = 1 + ay + ay2 +….. and a1 = a2 = 10, them (mn) is

Q2

If x is + ive, the first – ive term in the expansion of (1 + x)27/5 is:

Q3

Coefficients of x11 in the expansion of (2x2 + x – 3)6 is

Q4

Coefficients of x10 in the expansion of (1 + x2 – x3)8 is

Q5

The expression [x + (x3 - 1)1/2]5 + [x – (x3 – 1)1/2]5 is a polynomial of degree

Q6

The degree of the polynomial

              is equal to

Q7

 where {x} = Fractional part of x then the value of sec –1 (8θ) is

Q8

The remainder left out when 82n – (62)2n+1 is divided by 9 is

Q9
Q10

Sum of the last 30 coefficients in the expansion of (1 + x)59 when expanded in ascending powers of x is