﻿ A straight line L with negative slope passes through the point (8, 2) and cuts the positive coordinates axes at points P and Q. As L varies, the absolute minimum values of OP + OQ is (O is origin)     : Kaysons Education

# A Straight Line L With Negative Slope Passes Through The Point (8, 2) And Cuts The Positive Coordinates Axes At Points P And Q. As L Varies, The Absolute Minimum Values Of OP + OQ Is (O Is Origin)

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## Question

### Solution

Correct option is

18

The equation of line L be y – 2 = m (x – 8), m < 0

………..[Using A. M ≥ G.M]

Hence, absolute min value of OP + OQ = 18

#### SIMILAR QUESTIONS

Q1

Find the distance of line h (x + h) + k (y + k) = 0 from the origin.

Q2

Determine the distance between the lines : 6x + 8y – 45 = 0 and 3x + 4y – 5 = 0.

Q3

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Q4

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Q5

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Q6

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Q7

A and B are two fixed points. The vertex C of a Δ ABC moves such that cot A + cot B = constant. Locus of C is a straight line:

Q8

The number of integer values of m, for which the x-co-ordinate of the point of intersection of the lines 3x + 4y = 9 and y = mx + 1 is also an integer, is:

Q9

The vertices of a triangles are A (x1x1 tan α), B (x2x2 tan β) and C (x3,x3 tan γ). If the circumcentre of Δ ABC coincides with the origin and H (ab) be its orthocenter, then a/b is equal to:

Q10

Consider the family of lines

(x + y – 1) + λ (2x + 3y – 5) = 0

and   (3x + 2y – 4) + µ (x + 2y – 6) = 0

equation of a straight line that belongs to both the families is: