Question

Find the equation of the right bisector of the line joining (1, 1) and (3, 5).

Solution

Correct option is

x + 2y – 8 = 0

 

Let m be the slope of the line joining (1, 1) and (3, 5). 

  

∴ Slope (M) of right bisector of the join of (1, 1) and (3, 5) = .

  

Mid point of the join of (1, 1) and (3, 5) is 

i.e.,   (2, 3) 

Hence equation of the right bisector passing through (2, 3) and having slope M = –1/2 is   

          

or     x + 2y – 8 = 0.

SIMILAR QUESTIONS

Q1

 

Find the equation of the straight line which passes through the point (2, –3) and is  

1. parallel to the x-axis

2. perpendicular to the x-axis

Q2

Find the equation of a line which is equidistant from the lines .

Q3

If the straight line y = mx + c passes through the points (2, 4) and (–3, 6), find the values of m and c.

Q4

 

What are the inclination to the x-axis and intercept on y-axis of the line 

              ?

Q5

Find the equation of the straight line cutting off an intercept of 3 units on negative direction of y-axis and inclined at an angle  to the axis of x.

Q6

Find the equation to the straight line cutting off an intercept of 5 units on negative direction of y-axis and being equally inclined to the axes.  

Q7

 

Find the equations of the bisectors of the angle between the coordinate axes.

 

Q8

Find the equation of a line which makes an angle of 135o with positive direction of x-axis and passes through the point (3, 5).

Q9

Find the equation of the straight line bisecting the segment joining the points (5, 3) and (4, 4) and making an angle of 45o with the positive direction of x-axis.

Q10

Find the equation to the straight line joining the points .