﻿ Find the equation of the right bisector of the line joining (1, 1) and (3, 5). : Kaysons Education

# Find The Equation Of The Right Bisector Of The Line Joining (1, 1) And (3, 5).

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## Question

### Solution

Correct option is

x + 2y – 8 = 0

Let m be the slope of the line joining (1, 1) and (3, 5).

∴ Slope (M) of right bisector of the join of (1, 1) and (3, 5) = .

Mid point of the join of (1, 1) and (3, 5) is

i.e.,   (2, 3)

Hence equation of the right bisector passing through (2, 3) and having slope M = –1/2 is

or     x + 2y – 8 = 0.

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