## Question

Find the equation of the right bisector of the line joining (1, 1) and (3, 5).

### Solution

*x* + 2*y* – 8 = 0

Let *m* be the slope of the line joining (1, 1) and (3, 5).

∴ Slope (*M*) of right bisector of the join of (1, 1) and (3, 5) = .

Mid point of the join of (1, 1) and (3, 5) is .

i.e., (2, 3)

Hence equation of the right bisector passing through (2, 3) and having slope *M* = –1/2 is

or *x* + 2*y* – 8 = 0.

#### SIMILAR QUESTIONS

Find the equation of the straight line which passes through the point (2, –3) and is

1. parallel to the x-axis

2. perpendicular to the x-axis

Find the equation of a line which is equidistant from the lines .

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?

Find the equation of the straight line cutting off an intercept of 3 units on negative direction of y-axis and inclined at an angle to the axis of *x*.

Find the equation to the straight line cutting off an intercept of 5 units on negative direction of y-axis and being equally inclined to the axes.

Find the equations of the bisectors of the angle between the coordinate axes.

Find the equation of a line which makes an angle of 135^{o} with positive direction of *x*-axis and passes through the point (3, 5).

Find the equation of the straight line bisecting the segment joining the points (5, 3) and (4, 4) and making an angle of 45^{o} with the positive direction of x-axis.

Find the equation to the straight line joining the points .