﻿ The lines 2x – 3y = 5 and 3x – 4y = 7 are the diameters of a circle of area 154 square units. An equation of this circle is (π = 22/7) : Kaysons Education

The Lines 2x – 3y = 5 And 3x – 4y = 7 Are The Diameters Of A Circle Of Area 154 Square Units. An Equation Of This Circle Is (π = 22/7)

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Question

Solution

Correct option is

x2 + y2 – 2x + 2y = 47

The centre of the circle is the point of intersection of the given diameters 2x – 3y = 5 and 3x – 4y = 7, which is (1, –1) and if r is the radius of the circle,

Hence an equation of the required circle is

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