﻿   Find the equation of straight line which passes through the intersection of the straight lines           3x – 4y + 1 = 0 and 5x + y – 1 = 0  and cuts off equal intercepts from the axes. : Kaysons Education

# Find The Equation Of Straight Line Which Passes Through The Intersection Of The Straight Lines           3x – 4y + 1 = 0 And 5x + y – 1 = 0  And Cuts Off Equal Intercepts From The Axes.

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## Question

### Solution

Correct option is

23x + 23y = 11

Equation of any line passing through the intersection of the given lines is

(3x – 4y + 1) + λ(5x + y – 1) = 0

but given     x-intercept = y-intercept

(λ ≠ 1 âˆµ if λ = 1 then line (i) pass through origin)

Substituting the value of λ in (i), we get required equation is

23x + 23y = 11.

#### SIMILAR QUESTIONS

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Q9

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x + 5y + 7 = 0, 3x + 2y – 5 = 0 and

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2. perpendicular to the line 7x + 2y – 5 = 0

Q10

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