Question

The conic represented by the equation  is

Solution

Correct option is

Parabola

  

 (ax + by – 1)2 = 4abxy

 (ax – by)2 = 2(ax + by) – 1

Since second degree terms from perfect square.

SIMILAR QUESTIONS

Q1

If the parabola y2 = 4ax passes through the pint (1, –2), then the tangent at this point is

Q2

The equation of normal at the point  to the parabola y2 = 4ax, is

Q3

The equation of tangent at the point (1, 2) to the parabola y2 = 4ax, is

Q4

If a tangent of y2 = ax made angle of 450 with the x-axis, then its point of contact will be

Q5

If a normal drawn to the parabola y2 = 4ax at the point (a, 2a) meets parabola again on (at2, 2at), then the value of t will be

Q6

If the straight line x + y = 1 touches the parabola y2 – y + x = 0, then the coordinates of the point of contact are

Q7

The angle of intersection between the curves y2 = 4x and x2 = 32y at point (16, 8) is

Q8

The pole of the line lx + mx + n = 0 with respect to the parabola y2 = 4ax is

Q9

Two tangent are drawn from the point (–2, –1) to the parabola y2 = 4x. if  is the angle between them, then 

Q10

If (4, 0) is the vertex and y-axis, the directrix of a parabola then its focus is