Question

The vertex of the parabola y2 = 8x is at the center of a circle and the parabola cuts the circle at the ends of its latus rectum. Then the equation of the circle is

Solution

Correct option is

x2 + y2 = 20

Vertex = (0, 0). The ends of latus rectum are (2, 4), (2, – 4)

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SIMILAR QUESTIONS

Q1

The line  will touch the parabola y2 = 4a(x + a), if

Q2

The equation of the parabola whose axis is vertical and passes through the points (0, 0), (3, 0) and (–1, 4), is

Q3

The points on the parabola y2 = 36x whose ordinate is three times the abscissa are

Q4

The points on the parabola y2 = 12x whose focal distance is 4, are

Q5

Axis of the parabola x2 – 4x – 3+ 10 = 0 is  

Q6

The equation of the latus rectum of the parabola x2 + 4x + 2= 0 is 

Q7

x – 2 = t2y = 2t are the parameter equations of the parabola 

Q8

The equation  represents a parabola if  is

Q9

t1’ and ‘t2’ are two points on the parabola y2 = 4x. If the chord joining them is a normal to the parabola at ‘t1’ then

Q10

Find the equation of the parabola whose focus is (1, 1) and the directrix is x + y + 1 = 0.