﻿ The vertex of the parabola y2 = 8x is at the center of a circle and the parabola cuts the circle at the ends of its latus rectum. Then the equation of the circle is : Kaysons Education

# The Vertex Of The Parabola y2 = 8x is At The Center Of A Circle And The Parabola Cuts The Circle At The Ends Of Its Latus Rectum. Then The Equation Of The Circle Is

#### Video lectures

Access over 500+ hours of video lectures 24*7, covering complete syllabus for JEE preparation.

#### Online Support

Practice over 30000+ questions starting from basic level to JEE advance level.

#### National Mock Tests

Give tests to analyze your progress and evaluate where you stand in terms of your JEE preparation.

#### Organized Learning

Proper planning to complete syllabus is the key to get a decent rank in JEE.

#### Test Series/Daily assignments

Give tests to analyze your progress and evaluate where you stand in terms of your JEE preparation.

## Question

### Solution

Correct option is

x2 + y2 = 20

Vertex = (0, 0). The ends of latus rectum are (2, 4), (2, – 4)

.

#### SIMILAR QUESTIONS

Q1

The line  will touch the parabola y2 = 4a(x + a), if

Q2

The equation of the parabola whose axis is vertical and passes through the points (0, 0), (3, 0) and (–1, 4), is

Q3

The points on the parabola y2 = 36x whose ordinate is three times the abscissa are

Q4

The points on the parabola y2 = 12x whose focal distance is 4, are

Q5

Axis of the parabola x2 – 4x – 3+ 10 = 0 is

Q6

The equation of the latus rectum of the parabola x2 + 4x + 2= 0 is

Q7

x – 2 = t2y = 2t are the parameter equations of the parabola

Q8

The equation  represents a parabola if  is

Q9

t1’ and ‘t2’ are two points on the parabola y2 = 4x. If the chord joining them is a normal to the parabola at ‘t1’ then

Q10

Find the equation of the parabola whose focus is (1, 1) and the directrix is x + y + 1 = 0.