Find The Equation Of Tangent To The Circle x2 + y2 – 2ax = 0 At The Point  

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Question

Find the equation of tangent to the circle x2 + y2 – 2ax = 0 at the point  

Solution

Correct option is

 

The equation of tangent of x2 + y2 – 2ax = 0 at the point      

     

Testing

SIMILAR QUESTIONS

Q1

 

Find the equation of circle which touches axis of y at a distance 4 units from the origin and cuts the intercept of 6 units from the axis of x.

Equation of circle in intercepts  

               

                

Q2

Find the equation of the circle which passes through the origin and makes intercepts of length a and b on axis of x and y respectively.

Q3

A circle of radius 2 lies in the first quadrant and touches both the axes of coordinate. Find the equation of circle with centre at (6, 5) and touching the above circle externally.

Q4

A circle of radius 5 units touches the coordinates axes in 1st quadrant. If the circle makes one complete roll on x axis along positive direction of xaxis. Find the equation in new position. 

Q5

 

Discus the position of the points (1, 2) and (6, 0) with respect to the circle.

                 x2 + y2 – 4x + 2y – 11 = 0   

Q6

 

Find the shortest and largest distance from the point (2, –7) to the circle 

                 x2 + y2 – 14x – 10y – 151 = 0   

Q7

Find the length of intercept on the S.L. 4x – 3y – 10 = 0 by the circle x2y2 – 2x + 4y – 20 = 0.

Q8

Find the coordinates of the middle point of the chord which the circle x2y2 + 4x – 2y – 3 = 0 cut off the line x – y + 2 = 0.   

Q9

For what values of λ will the line y = 2x + λ be a tangent to the circle x2y2 = 5.

Q10

Find the equation of normal to the x2 + y2 = 2x which is parallel to x + 2y= 3.