﻿ The values of θ lying between 0 and π/2 and satisfying the equation                        : Kaysons Education

# The Values Of θ lying Between 0 And π/2 And Satisfying The Equation

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## Question

### Solution

Correct option is

7π/24 and 11π/24

Appling R1 → R1 – R3 and R2 → R2 – R3 on the L.H.S. the given equation can be written as

Expanding the LHS along R1, we get 1 + 4 sin 4θ + cos2 θ + sin2 θ = 0

∴ 4 sin 4θ = – 2 ⇒ sin 4θ = – 1/2

∴ 4θ = 7π/6 or 11π/6

[∴ 0 < θ < π/2 ⇒ 0 < 4θ  < 2π]

∴ θ = 7π/24 or 11π/24

#### SIMILAR QUESTIONS

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