﻿ If the equation of the locus of a point equidistant from the points (a1, b1) and (a2, b2) is (a1 – a1)x + (b1  –  b2)y + c = 0, Then the value of c is : : Kaysons Education

# If The Equation Of The Locus Of A Point Equidistant From The Points (a1, b1) And (a2, b2) Is (a1 – a1)x + (b1  –  b2)y + C = 0, Then The Value Of c is :

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## Question

### Solution

Correct option is

If A, B be the given points then the locus represents theright bisector ofAB. Hence it will pass through mid-point of AB, i.e.,

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