Question

If the equation of the locus of a point equidistant from the points

(a1b1) and (a2b2) is (a1 – a1)x + (b1  –  b2)y + c = 0,

Then the value of c is :

Solution

Correct option is

If A, B be the given points then the locus represents theright bisector ofAB. Hence it will pass through mid-point of AB, i.e.,

SIMILAR QUESTIONS

Q1

a and b real numbers between 0 and 1 A(a, 1), B(1, b) andC(0, 0) are the vertices of triangle

1:- If the triangle ABC is equilateral, its area is equal to

Q2

If the triangle ABC in  isosceles with AC = BC and 5(AB)2 = 2(AC)2 then

Q3

The origin is shifted to(1, –2)then what are the coordinates be shifted if the point (3, –5) in the new position?

Q4

If the origin is shifted to (1, –2), the coordinates of A become (2, 3). What are the original coordinates of A?

Q5

Determiner as to what point the axes of the coordinates be shifted so as to remove the first degree terms from the equation

           (x, y) = 2x2 + 3y2 – 12x + 12+ 24 = 0

Q6

What will be the coordinates of the point  when the axes are rotated through an angle of 300 in clockwise sense?

Q7

What will be the coordinates of the point in original position ifr its coordinates after rotation of axes through an angle 600  ?

Q8

The in centre of the triangle with vertices , (0, 0) and (2, 0) is

Q9

If a vertex of a triangle is (1, 1) and the mid-point of two sides through the vertex are (–1, 2) and (3, 2), then the centroid of the triangle is

Q10

The line joining the point  is produced to the point L(x, y) so that AL : LB b : a, then