## Question

### Solution

Correct option is (I) Ellipse ⇒ ae = 4, so focus is

S(ae, 0) = S(4, 0)                                       ….. (1)

(II) Hyperbola e1 = 2 focus is at S(2a, 0). So by

assumption (1) & (2) represent the same            ….. (2) .

#### SIMILAR QUESTIONS

Q1

The eccentricity of the conjugate hyperbola of the hyperbola x2 – 3y2 = 1 is

Q2

The distance between the directrices of a rectangular hyperbola is 10 units, then distance between its foci is

Q3

The ,locus of the middle points of portions of the tangents to the hyperbola , intercepted between the axes is

Q4

If the polar of a point with respect to toches the hyperbola , then the locus of the point is

Q5

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Q6

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Q7

PN is the ordinate of any point P on the hyperbola and AA’ is its transverse axis. If Q divides AP in the ratio a2 : b2, then NQ is

Q8

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Q9

The lines 2x + 3y + 4 = 0 and 3x – 2y + 5 = 0 may be conjugate w.r.t. the hyperbola if

Q10

The condition for two diameters of a hyperbola represented by Ax2 + 2Hxy + By2 = 0 to be conjugate is