Question

The vertices of a triangle are A(10, 4), B(–4, 9) and C(–2, –1). Find the equation of the altitude through A.

Solution

Correct option is

x – 5y + 10 = 0

 

               

 

Hence, equation of altitude AD which passes through (0, 4) and having slope 1/5 is    

         

or      x – 5y + 10 = 0

SIMILAR QUESTIONS

Q1

 

What are the inclination to the x-axis and intercept on y-axis of the line 

              ?

Q2

Find the equation of the straight line cutting off an intercept of 3 units on negative direction of y-axis and inclined at an angle  to the axis of x.

Q3

Find the equation to the straight line cutting off an intercept of 5 units on negative direction of y-axis and being equally inclined to the axes.  

Q4

 

Find the equations of the bisectors of the angle between the coordinate axes.

 

Q5

Find the equation of a line which makes an angle of 135o with positive direction of x-axis and passes through the point (3, 5).

Q6

Find the equation of the straight line bisecting the segment joining the points (5, 3) and (4, 4) and making an angle of 45o with the positive direction of x-axis.

Q7

Find the equation of the right bisector of the line joining (1, 1) and (3, 5).

Q8

Find the equation to the straight line joining the points .

Q9

 

Let ABC be a triangle with A(–1, –5), B(0, 0) and C(2, 2) and let D be the middle point of BC. Find the equation of the perpendicular drawn from Bto AD.  

 

Q10

Find the equations of the medians of a triangle, the coordinates of whose vertices are (–1, 6), (–3, –9) and (5, –8).