## Question

### Solution

Correct option is

m /2m–1

Let A denote the event that there is an odd man out in a game. The total number of possible cases is 2m. A person is odd man out if he is alone in getting a head or a tail. The number of ways in which there is exactly one tail (head) and the rest are heads (tails) is .

Thus, the number of favorable ways is m + 2m. Therefore, #### SIMILAR QUESTIONS

Q1

In a hurdle race, a runner has probability p of jumping over a specific hurdle. Given that in 5 trials, the runner succeeded 3 times, the conditional probability that the runner had succeeded in the first trial is

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Q3

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Q4

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Q5

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Q6

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Q8

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Q9

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Q10

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