Question

The odd against a certain event are 5: 2 and the odds in favour of another independent event are 6: 5 the probability that at least one of the events will happen is:

Solution

Correct option is

52/77

Let the first event be E and second Event be F

⇒ P(at least one of events)

       = 1 – P(none of the event happen)

       

       

SIMILAR QUESTIONS

Q1

A box contains tickets numbered 1 to Nn tickets are drawn from the box with replacement. The probability that the largest number on the tickets is is

Q2

A box contain N coins, m of which are fair and rest are biased. The probability of getting a head when a fair coin is tossed is 1/2, when a baised coin is tossed. A coin is drawn from the box at random and is tossed twice. The first time it shows head and the second time it shows tail. The probability that the coin drawn is fair is

Q3

Given that AB and C are events such that P(A) = P(B) = P(C) = 1/5, P(A B) = P(B ∩ C) = 0 and P(A ∩ C) = 1=10. The probability that at least one of the events AB or C occurs is …….

Q4

 

Let A and B be two events such that

Q5

A and B toss a coin alternatively till one of them gets a head and wins the game. If A begins the game, the probability B wins the game is

Q6

Suppose X B(np) and P(X = 5). If p > 1/2, then

Q7

A person is known to speak the truth 4 time out of 5. He throws a dia and reports that it is a ace. The probability that it is actually a ace is

Q8

In a game called “odd man out man out”, m(m > 2) persons toss a coin to determine who will buy refreshments for the entire group. A person who gets an outcome different from that of the rest of the members of the group is called the odd man out. The probability that there is a loser in any game is

Q9

 

The chance of an event happening is the square of the chance of happening of second event but the odds against the first are the cube of the odds against the second. The chance of the events:

Q10

If A1, A2,….An are any n events, then