## Question

### Solution

Correct option is

1.2

At least one:       P(A ∪ B) = 0.6

Simultaneous:    P(A ∩ B) = 0.2

We know            P(A ∪ B) + P(A ∩ B) = P(A) + P(B)

⇒                       P(A) + P(B) = 0.8  #### SIMILAR QUESTIONS

Q1

Given that AB and C are events such that P(A) = P(B) = P(C) = 1/5, P(A B) = P(B ∩ C) = 0 and P(A ∩ C) = 1=10. The probability that at least one of the events AB or C occurs is …….

Q2

Let A and B be two events such that Q3

A and B toss a coin alternatively till one of them gets a head and wins the game. If A begins the game, the probability B wins the game is

Q4

Suppose X B(np) and P(X = 5). If p > 1/2, then

Q5

A person is known to speak the truth 4 time out of 5. He throws a dia and reports that it is a ace. The probability that it is actually a ace is

Q6

In a game called “odd man out man out”, m(m > 2) persons toss a coin to determine who will buy refreshments for the entire group. A person who gets an outcome different from that of the rest of the members of the group is called the odd man out. The probability that there is a loser in any game is

Q7

The chance of an event happening is the square of the chance of happening of second event but the odds against the first are the cube of the odds against the second. The chance of the events:

Q8

The odd against a certain event are 5: 2 and the odds in favour of another independent event are 6: 5 the probability that at least one of the events will happen is:

Q9

If A1, A2,….An are any n events, then

Q10

Odds in favour of an event A is 2 to 1 and odds in favour of A∪ B are 3 to 1. Consistent with information the smallest and largest values for the probability of event B are given by: