## Question

The probability that at least one of the event A and B occurs is 0.6 if A and B occur simultaneously with probability 0.2, then

### Solution

1.2

At least one: *P*(*A* ∪ *B*) = 0.6

Simultaneous: *P*(*A* ∩ *B*) = 0.2

We know *P*(*A* ∪ *B*) + *P*(*A* ∩ *B*) = *P*(*A*) + *P*(*B*)

⇒ *P*(*A*) + *P*(*B*) = 0.8

#### SIMILAR QUESTIONS

Given that *A*, *B* and *C* are events such that *P*(*A*) = *P*(*B*) = *P*(*C*) = 1/5, *P*(*A*∩ *B*) = *P*(*B* ∩ *C*) = 0 and *P*(*A* ∩ *C*) = 1=10. The probability that at least one of the events *A*, *B* or *C* occurs is …….

Let A and B be two events such that

A and B toss a coin alternatively till one of them gets a head and wins the game. If A begins the game, the probability B wins the game is

Suppose X ~ *B*(*n*, *p*) and *P*(*X* = 5). If *p* > 1/2, then

A person is known to speak the truth 4 time out of 5. He throws a dia and reports that it is a ace. The probability that it is actually a ace is

In a game called “odd man out man out”, *m*(*m* > 2) persons toss a coin to determine who will buy refreshments for the entire group. A person who gets an outcome different from that of the rest of the members of the group is called the odd man out. The probability that there is a loser in any game is

The chance of an event happening is the square of the chance of happening of second event but the odds against the first are the cube of the odds against the second. The chance of the events:

The odd against a certain event are 5: 2 and the odds in favour of another independent event are 6: 5 the probability that at least one of the events will happen is:

If A_{1}, A_{2},….A* _{n}* are any

*n*events, then

Odds in favour of an event A is 2 to 1 and odds in favour of A∪ B are 3 to 1. Consistent with information the smallest and largest values for the probability of event B are given by: